7p(p-1)=7(4+p^2)

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Solution for 7p(p-1)=7(4+p^2) equation: 



7p(p-1)=7(4+p^2)

We move all terms to the left:

7p(p-1)-(7(4+p^2))=0

We multiply parentheses

-(7(4+p^2))+7p^2-7p=0



We calculate terms in parentheses: -(7(4+p^2)), so:

7(4+p^2)

We multiply parentheses

7p^2+28

Back to the equation:

-(7p^2+28)



We add all the numbers together, and all the variables

7p^2-7p-(7p^2+28)=0

We get rid of parentheses

7p^2-7p^2-7p-28=0

We add all the numbers together, and all the variables

-7p-28=0

We move all terms containing p to the left, all other terms to the right

-7p=28

p=28/-7

p=-4

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